Please peeps help me! Maths p(t) = p0(10-8e^t)? - p0 p tropica
Eh!
There are three parts to this question. I'm really not, if you know the answer, can you explain possible in this simplified form. (the brain is a bit slow after Christmas and everything, LOL)
A species has a population P (t) at any time
P (t) = P0 (10-8e ^ t)
A) Make a diagram of the PT for P0 = 1 and the values of t between 0 and 5
Use this table to comment on trends in the population. Are there threatening an extinction?
B) Let P0 = 1000 What is the size of the population of the species, such as t is very large?
Considering C) for P0 = 1000 and the population at time t = 0 as reference, how long does it take to double the money?
All references are helpful, EB! Oh, and itdue in 7 (thats Monday)
NOTE - = less (less than T)
thank everyone in advance, keep smiling hope that everyone had a wicked crimbo and new year! :-)
Sunday, February 14, 2010
P0 P Tropica Please Peeps Help Me! Maths P(t) = P0(10-8e^t)?
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2 comments:
havent done it's ok for a few years, but here:
A: The question is therefore:
p = 10-8e ^ (-t)?
Notes:
t = 0
e ^ 0 = 1 for 10-8 = 2
t = 1
e ^ -1 = 0.368 for (10 to 8-fold (0.368)) = 7.06
To find answers + 2 3 4 5
t = 5
10-8e ^ -5 = 9.95
from the viewpoint of the 8th - ^ t to 0 as the focal point of 10
(this helps the next section)
B simply insert into your computer --
1000 (10-8e ^ -9999999)
-9999999 E ^ = 0
and p (t) v 1000x (10-0) = 10000
The last part
p (T0) = 1000 (10-8e ^ -0) = 2000
Search for a population of 4000 .... t
Reorganization and taking natural logs:
1000 (10-8e ^-t) =4000
4 = 10 ^-T-8th
14 / 8 =- e ^-t
ln (1.75) = your answer
... I think ....?
long time since I've done
A) Here are the points on Property
t = 0 p (t) = 2
T = 1, p (t) = -11.75
t = 2 p (t) = -49.11
t 3 = p (t) = -150.68
t = 4 p (t) = -426.79
t = 5 p (t) = -1177.31
No danger of extinction at this time but if the trend continues, there is. The population continues to decline.
B)
P (t) = 1000 (10-8e ^ t)
P (t) = 10000-t ^ 8000th
Since t -> infinity and infinity ^ t -> t, and becomes very large, the size of the population decreases rapidly and it is an endangered species ..
t = 10 p (t) = -176.201.726,36
t = 11 p (t) = -478.983.133,72
t = 12 p (t) = -1302028331.35
t = 13 p (t) = -3539297136.07
t = 14 p (t) = -9620824273.32
t = 15 p (t) = -26152128979.78
t = 16 p (t) = -71088874164.06
t = 17 p (t) = -193239612028.6 \\ \\ \\ \\ \\ \\ \\ \\ u0026lt;br> T = 18, p (t) = -525279743098.64
t = 19 p (t) = -1427858397705.5
t = 20 p (t) = -3881321553278.32
It is true that when t becomes very large, the population goes extinct.
C)
P (t) = 1000 (10-8e ^ t)
if t = 0, p (t) = 1000 (2) = 2000, where p (0) = 1000
When doulas
Solution for t
4000 = 1000 (10-8e ^ t)
4 = 10-8e ^ t
-6 =- 8e ^ t
e ^ t = 6 / 8 = 0.75
t = ln (0.75)
t =- 0.125 (?)
The question is confusing. Maintain species decreased. How can bend and at some point in time?
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